The decreasing order of size of the isoelectr | vedclass

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Question

(D) For isoelectronic species,the ionic radius decreases as the nuclear charge (atomic number,$Z$) increases because the effective nuclear attraction

Vedclass · Accepted Answer

$S^{2-} > Cl^{-} > K^{+} > Ca^{2+}$

Vedclass · Answer

(D) For isoelectronic species,the ionic radius decreases as the nuclear charge (atomic number,$Z$) increases because the effective nuclear attraction on the electrons increases.The atomic numbers are: $S (Z=16)$,$Cl (Z=17)$,$K (Z=19)$,and $Ca (Z=20)$.Since all these ions have the same number of electrons ($18$ electrons),the size follows the order of increasing atomic number: $S^{2-} (Z=16) > Cl^{-} (Z=17) > K^{+} (Z=19) > Ca^{2+} (Z=20)$.Therefore,the correct decreasing order is $S^{2-} > Cl^{-} > K^{+} > Ca^{2+}$.

$A$. Element	$B$. Atomic Radius $(pm)$
$A$. $Be$	$I$. $74$
$B$. $C$	$II$. $77$
$C$. $O$	$III$. $66$
$D$. $B$	$IV$. $88$
$E$. $N$	$V$. $111$

The decreasing order of size of the isoelectronic series $K^{+}$,$Ca^{2+}$,$Cl^{-}$,and $S^{2-}$ is:

Similar Questions

Which of the following is the incorrect order of ionic/atomic radius?

Match the elements in Column-$A$ with their correct atomic radii in Column-$B$ (in $pm$).

$A$. Element $B$. Atomic Radius $(pm)$

$A$. $Be$ $I$. $74$

$B$. $C$ $II$. $77$

$C$. $O$ $III$. $66$

$D$. $B$ $IV$. $88$

$E$. $N$ $V$. $111$

The increasing order of the atomic radius of $Si, S, Na, Mg, Al$ is

Which of the following sets of ions represents a group of isoelectronic species?

Describe the theory associated with the radius of an atom as it:
$(a)$ Gains an electron
$(b)$ Loses an electron

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