The decreasing order of basicity for the foll | vedclass

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(A) The basicity of amines depends on the availability of the lone pair of electrons on the nitrogen atom.In compound $(III)$ (piperidine),the nitroge

Vedclass · Accepted Answer

$III > I > II$

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(A) The basicity of amines depends on the availability of the lone pair of electrons on the nitrogen atom.In compound $(III)$ (piperidine),the nitrogen atom is $sp^3$ hybridized,and the lone pair is localized,making it the most basic.In compound $(I)$ (pyridine),the nitrogen atom is $sp^2$ hybridized. The lone pair is in an $sp^2$ orbital,which is more electronegative than an $sp^3$ orbital,making it less basic than $(III)$.In compound $(II)$ (pyrrole),the lone pair of electrons on the nitrogen atom participates in the aromatic sextet (delocalization). Therefore,it is not available for protonation,making it the least basic.Thus,the decreasing order of basicity is $III > I > II$.

The decreasing order of basicity for the following amine compounds is:

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