The de-Broglie wavelength of a particle with mass $1 \, g$ and velocity $100 \, m/sec$ is

The de Broglie wavelength is given as $1 \, \mathring{A}$ and the value of $h$ is $6.6252 \times 10^{-27} \, \text{erg} \cdot \text{s}$. What will be the momentum of the particle (in $\text{g} \cdot \text{cm/s}$)?

The de Broglie wavelength of a particle of mass $1 \ mg$ moving with a velocity of $10 \ m \ s^{-1}$ is $(h=6.63 \times 10^{-34} \ J \ s)$

The wavelength associated with a particle of mass $9.109 \times 10^{-31} \ kg$ moving with a velocity of $1.20 \times 10^5 \ m/s$ is ....... meters.

If the velocities of hydrogen $(H_2)$ and helium $(He)$ molecules are equal,then the ratio of the wavelengths of helium to hydrogen is .......

The following plot represents the de-Broglie wavelength $(\lambda)$ as a function of $\frac{1}{\sqrt{K.E.}}$ for two particles $A$ and $B$. Identify the correct relation between their masses ($m_A$ and $m_B$).