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(B) According to the equation of continuity, the volume flow rate remains constant throughout the system.$A_{1} v_{1} = A_{2} v_{2}$Here, $A_{1} = 8 \

Vedclass · Accepted Answer

$5$

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(B) According to the equation of continuity, the volume flow rate remains constant throughout the system.$A_{1} v_{1} = A_{2} v_{2}$Here, $A_{1} = 8 \,cm^{2} = 8 	imes 10^{-4} \,m^{2}$.The speed inside the tube is $v_{1} = 0.15 \,m \,min^{-1} = \frac{0.15}{60} \,m \,s^{-1} = 0.0025 \,m \,s^{-1}$.The total area of the $40$ holes is $A_{2} = 40 	imes 10^{-8} \,m^{2}$.Substituting these values into the continuity equation:$(8 	imes 10^{-4}) 	imes (0.0025) = (40 	imes 10^{-8}) 	imes v_{2}$$v_{2} = \frac{8 	imes 10^{-4} 	imes 0.0025}{40 	imes 10^{-8}}$$v_{2} = \frac{2 	imes 10^{-6}}{40 	imes 10^{-8}} = \frac{200}{40} = 5 \,m \,s^{-1}$.Thus, the speed with which the liquid is ejected is $5 \,m \,s^{-1}$.

The cylindrical tube of a spray pump has a cross-section of $8 \,cm^{2}$, one end of which has $40$ fine holes each of area $10^{-8} \,m^{2}$. If the liquid flows inside the tube with a speed of $0.15 \,m \,min^{-1}$, the speed with which the liquid is ejected through the holes is (in $\,ms^{-1}$)

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