The current through an inductor is given by i | vedclass

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(A) The induced $emf$ in an inductor is given by $e = -L \frac{di}{dt}$.Given $i = 10 + 20t$,we have $\frac{di}{dt} = 20 \, A/s$.The magnitude of $emf

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$10$

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(A) The induced $emf$ in an inductor is given by $e = -L \frac{di}{dt}$.Given $i = 10 + 20t$,we have $\frac{di}{dt} = 20 \, A/s$.The magnitude of $emf$ is $|e| = L \left| \frac{di}{dt} ight| = 4 \, V$.Thus,$L 	imes 20 = 4$,which gives $L = 0.2 \, H$.The total flux linked with the inductor is $\Phi = L \cdot i$.At $t = 2 \, s$,the current is $i = 10 + 20(2) = 50 \, A$.Therefore,the total flux $\Phi = 0.2 	imes 50 = 10 \, Wb$.

The current through an inductor is given by $i = (10 + 20t) \, A$,where $t$ is in $s$. The induced $emf$ in the inductor is $4 \, V$. The total flux linked with the inductor at $t = 2 \, s$ is ...... $Wb$.

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