The current passing through a coil of $120$ turns and inductance $40 \text{ mH}$ is $30 \text{ mA}$. The magnetic flux linked with the coil is:

  • A
    $20 \times 10^{-6} \text{ Wb}$
  • B
    $5 \times 10^{-6} \text{ Wb}$
  • C
    $12 \times 10^{-6} \text{ Wb}$
  • D
    $10 \times 10^{-6} \text{ Wb}$

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