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(D) From the circuit diagram,the resistors $R_B = 6 \, \Omega$ and $R_C = 6 \, \Omega$ are connected in series.Their equivalent resistance is $R_{BC}

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$2$

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(D) From the circuit diagram,the resistors $R_B = 6 \, \Omega$ and $R_C = 6 \, \Omega$ are connected in series.Their equivalent resistance is $R_{BC} = 6 \, \Omega + 6 \, \Omega = 12 \, \Omega$.This combination $R_{BC}$ is in parallel with resistor $R_A = 3 \, \Omega$.The equivalent resistance $R_{eq}$ of the circuit is given by $\frac{1}{R_{eq}} = \frac{1}{R_A} + \frac{1}{R_{BC}} = \frac{1}{3} + \frac{1}{12} = \frac{4 + 1}{12} = \frac{5}{12} \, \Omega^{-1}$.Thus,$R_{eq} = \frac{12}{5} = 2.4 \, \Omega$.The total current $I$ in the circuit is $I = \frac{V}{R_{eq}} = \frac{4.8 \, V}{2.4 \, \Omega} = 2 \, A$.

The current in the given circuit is ............ $A$.

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