The current drawn from the battery in the giv | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The given circuit is a balanced Wheatstone bridge because the ratio of resistances in the arms is $\frac{3}{2} = \frac{3}{2}$.Since the bridge is

Vedclass · Accepted Answer

$2.4$

Vedclass · Answer

(A) The given circuit is a balanced Wheatstone bridge because the ratio of resistances in the arms is $\frac{3}{2} = \frac{3}{2}$.Since the bridge is balanced,no current flows through the central $5 \Omega$ resistor.Therefore,the $5 \Omega$ resistor can be removed from the circuit.Now,the upper branch consists of a $3 \Omega$ and $2 \Omega$ resistor in series,giving a total resistance of $3 + 2 = 5 \Omega$.The lower branch also consists of a $3 \Omega$ and $2 \Omega$ resistor in series,giving a total resistance of $3 + 2 = 5 \Omega$.These two branches are connected in parallel across the $6 	ext{ V}$ battery.The equivalent resistance $R_{eq}$ of the two $5 \Omega$ resistors in parallel is $R_{eq} = \frac{5 	imes 5}{5 + 5} = 2.5 \Omega$.The current drawn from the battery is $I = \frac{V}{R_{eq}} = \frac{6}{2.5} = 2.4 	ext{ A}$.

The current drawn from the battery in the given network is (Internal resistance of the battery is negligible). (in $A$)

Similar Questions

If a current of $7 \ A$ flows through the electric circuit,what is the potential difference between $B$ and $C$ in volts?

In the circuit shown,the currents (in $A$) through the $50\; V$ and $30\; V$ batteries are,respectively:

In the given circuit,if the potential at point $B$ is $24 \ V$,the potential at point $A$ is: (in $V$)

In the following circuit, the magnitude of current $I_1$ is $............A$.

The current drawn from the battery in the given network is (Internal resistance of the battery is negligible). (in $A$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module