The current between B and D in the given figu | vedclass

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(C) The given circuit is a Wheatstone bridge. Let the resistances be $P = 30 \ \Omega$ (between $A$ and $B$),$Q = 30 \ \Omega$ (between $B$ and $C$),$

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$0$

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(C) The given circuit is a Wheatstone bridge. Let the resistances be $P = 30 \ \Omega$ (between $A$ and $B$),$Q = 30 \ \Omega$ (between $B$ and $C$),$R = 30 \ \Omega$ (between $A$ and $D$),and $S = 30 \ \Omega$ (between $D$ and $C$). For a Wheatstone bridge to be balanced,the condition is $\frac{P}{R} = \frac{Q}{S}$. Substituting the values,we get $\frac{30}{30} = \frac{30}{30}$,which simplifies to $1 = 1$. Since the bridge is balanced,the potential at point $B$ is equal to the potential at point $D$. Therefore,the potential difference between $B$ and $D$ is $0 \ V$. As a result,no current flows through the $60 \ \Omega$ resistor connected between $B$ and $D$.

The current between $B$ and $D$ in the given figure is .............. $A$.

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