The current and voltage functions in an AC ci | vedclass

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(B) The formula for average power dissipated in an $AC$ circuit is $P = V_{rms} I_{rms} \cos \phi$.Given:$V_0 = 100 \, V$$I_0 = 100 \, mA = 0.1 \, A$P

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$2.5$

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(B) The formula for average power dissipated in an $AC$ circuit is $P = V_{rms} I_{rms} \cos \phi$.Given:$V_0 = 100 \, V$$I_0 = 100 \, mA = 0.1 \, A$Phase difference $\phi = \frac{\pi}{3}$.Calculate $V_{rms}$ and $I_{rms}$:$V_{rms} = \frac{V_0}{\sqrt{2}} = \frac{100}{\sqrt{2}} \, V$$I_{rms} = \frac{I_0}{\sqrt{2}} = \frac{0.1}{\sqrt{2}} \, A$Calculate power factor:$\cos \phi = \cos(\frac{\pi}{3}) = \frac{1}{2} = 0.5$.Substitute values into the power formula:$P = (\frac{100}{\sqrt{2}}) 	imes (\frac{0.1}{\sqrt{2}}) 	imes 0.5$$P = \frac{100 	imes 0.1}{2} 	imes 0.5$$P = \frac{10}{2} 	imes 0.5 = 5 	imes 0.5 = 2.5 \, W$.

The current and voltage functions in an $AC$ circuit are:
$I = 100 \sin(100t) \, mA$
$V = 100 \sin(100t + \frac{\pi}{3}) \, V$
The power dissipated in the circuit is ...... $W$.

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The current and voltage functions in an $AC$ circuit are:$I = 100 \sin(100t) \, mA$$V = 100 \sin(100t + \frac{\pi}{3}) \, V$The power dissipated in the circuit is ...... $W$.