The critical temperatures of gases A, B, C, a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The extent of physical adsorption of a gas on a solid surface is directly proportional to its ease of liquefaction.Easier liquefaction is indicate

Vedclass · Accepted Answer

$A$

Vedclass · Answer

(D) The extent of physical adsorption of a gas on a solid surface is directly proportional to its ease of liquefaction.Easier liquefaction is indicated by a higher critical temperature $(T_c)$.Therefore,gases with higher critical temperatures are adsorbed to a greater extent.The critical temperatures are: $B (630 \ K) > D (400 \ K) > C (261 \ K) > A (190 \ K)$.Thus,the order of adsorption is $B > D > C > A$.The gas with the lowest critical temperature will have the least amount adsorbed.Hence,gas $A$ has the least quantity adsorbed.

The critical temperatures of gases $A, B, C,$ and $D$ are $190 \ K, 630 \ K, 261 \ K,$ and $400 \ K$ respectively. The quantity of gas adsorbed per gram of charcoal at the same pressure is least for the gas:

Similar Questions

Methylene blue,from its aqueous solution,is adsorbed on activated charcoal at $25 \ ^{\circ}C$. For this process,the correct statement is

What type of phenomenon is adsorption? What type of reaction is adsorption?

Which type of bond is involved in the phenomenon of physical adsorption?

Give uses of silica gel.

Which of the following statements is correct for physisorption?

Vedclass Test Series

Exam Paper Generator

Online Exam Module