The covalent character of $CaCl_2, BaCl_2, SrCl_2$ and $MgCl_2$ follows the order:
- A$BaCl_2 < SrCl_2 < CaCl_2 < MgCl_2$
- B$MgCl_2 < CaCl_2 < SrCl_2 < BaCl_2$
- C$CaCl_2 < BaCl_2 < MgCl_2 < SrCl_2$
- D$SrCl_2 < MgCl_2 < CaCl_2 < BaCl_2$
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Similar Questions
Which among the following is the correct decreasing order of covalent character of ionic bonds?
Amongst $LiCl$,$RbCl$,$BeCl_2$,and $MgCl_2$,the compounds with the greatest and the least ionic character,respectively,are:
DifficultJEE MAIN 2014
View SolutionArrange the following in increasing order of their covalent character.
$CaF_{2}$,$CaCl_{2}$,$CaBr_{2}$,$CaI_{2}$
Choose the correct answer from the options given below.
$CaF_{2}$,$CaCl_{2}$,$CaBr_{2}$,$CaI_{2}$
Choose the correct answer from the options given below.
Define polarization.
Easy
View SolutionThe correct sequence of increasing covalent character is represented by
MediumAIPMT 2005
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