The correct statement(s) regarding (i) HClO,( | vedclass

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(B) Let us analyze the structures of the oxoacids of chlorine:$(i) HClO$: $H-O-Cl$ ($3$ lone pairs on $Cl$)$(ii) HClO_2$: $H-O-Cl=O$ ($2$ lone pairs o

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$(B, C)$

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(B) Let us analyze the structures of the oxoacids of chlorine:$(i) HClO$: $H-O-Cl$ ($3$ lone pairs on $Cl$)$(ii) HClO_2$: $H-O-Cl=O$ ($2$ lone pairs on $Cl$,$1$ $Cl=O$ bond)$(iii) HClO_3$: $H-O-Cl(=O)_2$ ($1$ lone pair on $Cl$,$2$ $Cl=O$ bonds)$(iv) HClO_4$: $H-O-Cl(=O)_3$ ($0$ lone pairs on $Cl$,$3$ $Cl=O$ bonds)Evaluating the statements:$(A)$ Number of $Cl=O$ bonds in $(ii)$ is $1$ and in $(iii)$ is $2$. Total = $3$. Statement $(A)$ is incorrect.$(B)$ Number of lone pairs on $Cl$ in $(ii)$ is $2$ and in $(iii)$ is $1$. Total = $3$. Statement $(B)$ is correct.$(C)$ In $HClO_4$,$Cl$ is bonded to $4$ oxygen atoms (one $-OH$ and three $=O$). Steric number = $4+0 = 4$,so hybridization is $sp^3$. Statement $(C)$ is correct.$(D)$ Acidic strength increases with the number of oxygen atoms attached to the central atom. Thus,$HClO_4$ is the strongest acid,not $HClO$. Statement $(D)$ is incorrect.Therefore,the correct statements are $(B)$ and $(C)$.

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