The correct statement about the magnetic prop | vedclass

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Question

(A) For $[Fe(CN)_6]^{3-}$,the oxidation state of $Fe$ is $+3$. The electronic configuration of $Fe^{3+}$ is $[Ar] 3d^5$. Since $CN^-$ is a strong fiel

Vedclass · Accepted Answer

both are paramagnetic

Vedclass · Answer

(A) For $[Fe(CN)_6]^{3-}$,the oxidation state of $Fe$ is $+3$. The electronic configuration of $Fe^{3+}$ is $[Ar] 3d^5$. Since $CN^-$ is a strong field ligand,it causes pairing of electrons,resulting in one unpaired electron $(n=1)$. Thus,it is paramagnetic.For $[FeF_6]^{3-}$,the oxidation state of $Fe$ is $+3$. The electronic configuration of $Fe^{3+}$ is $[Ar] 3d^5$. Since $F^-$ is a weak field ligand,it does not cause pairing,resulting in five unpaired electrons $(n=5)$. Thus,it is also paramagnetic.Therefore,both complexes are paramagnetic.

The correct statement about the magnetic properties of $[Fe(CN)_6]^{3-}$ and $[FeF_6]^{3-}$ is $(Z = 26)$.

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