The correct statement(s) about Cr^{2+} and Mn | vedclass

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(A, B, C, D) $(1)$ $Cr^{2+}$ $(d^4)$ is a reducing agent because it gets oxidized to $Cr^{3+}$ $(d^3)$,which has a stable half-filled $t_{2g}$ subshel

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$(A, B, C)$

Vedclass · Answer

(A, B, C, D) $(1)$ $Cr^{2+}$ $(d^4)$ is a reducing agent because it gets oxidized to $Cr^{3+}$ $(d^3)$,which has a stable half-filled $t_{2g}$ subshell.$(2)$ $Mn^{3+}$ $(d^4)$ is an oxidizing agent because it gets reduced to $Mn^{2+}$ $(d^5)$,which has a stable half-filled $d$-orbital configuration.$(3)$ Both $Cr^{2+}$ and $Mn^{3+}$ have $d^4$ electronic configuration.$(4)$ Since all statements $(A), (B), (C),$ and $(D)$ are correct,the correct option is $(A, B, C, D)$ (Note: Given the provided options,all statements are factually correct).

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