The correct statement(s) related to processes | vedclass

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(B) Roasting of Malachite $(CuCO_3 \cdot Cu(OH)_2)$ produces $CuO$ (Tenorite),not Cuprite $(Cu_2O)$. Thus,$(A)$ is incorrect.$(B)$ Calcination of Cala

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$B, C, D$

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(B) Roasting of Malachite $(CuCO_3 \cdot Cu(OH)_2)$ produces $CuO$ (Tenorite),not Cuprite $(Cu_2O)$. Thus,$(A)$ is incorrect.$(B)$ Calcination of Calamine $(ZnCO_3)$ produces Zincite $(ZnO)$: $ZnCO_3 \rightarrow ZnO + CO_2$. Thus,$(B)$ is correct.$(C)$ Copper pyrites $(CuFeS_2)$ is heated with silica $(SiO_2)$ in a reverberatory furnace. $FeO$ reacts with $SiO_2$ to form $FeSiO_3$ (slag): $FeO + SiO_2 \rightarrow FeSiO_3$. Thus,$(C)$ is correct.$(D)$ Impure silver is treated with aqueous $KCN$ in the presence of air $(O_2)$ to form a soluble complex,which is then reduced by $Zn$: $4Ag + 8CN^- + 2H_2O + O_2 \rightarrow 4[Ag(CN)_2]^- + 4OH^-$; $2[Ag(CN)_2]^- + Zn \rightarrow [Zn(CN)_4]^{2-} + 2Ag$. Thus,$(D)$ is correct.Therefore,the correct statements are $(B)$,$(C)$,and $(D)$.

List-$I$	List-$II$
$A$. Calcination	$1$. Galena
$B$. Roasting	$2$. Magnetite
$C$. Magnetic separation	$3$. Pyrometallurgy
$D$. Carbon reduction of metal oxide	$4$. Malachite

Similar Questions

Match the items of List-$I$ with those of List-$II$ and choose the correct option given below.
List-$I$ List-$II$
$A$. Calcination $1$. Galena
$B$. Roasting $2$. Magnetite
$C$. Magnetic separation $3$. Pyrometallurgy
$D$. Carbon reduction of metal oxide $4$. Malachite

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