The correct solubility order is/are:I. CaCO_3 | vedclass

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(D) For alkaline earth metal carbonates $(Group \ 2)$,the solubility decreases down the group because the lattice energy decreases less rapidly than t

Vedclass · Accepted Answer

$I, II, III$

Vedclass · Answer

(D) For alkaline earth metal carbonates $(Group \ 2)$,the solubility decreases down the group because the lattice energy decreases less rapidly than the hydration energy as the cation size increases. Thus,the order is $BeCO_3 > MgCO_3 > CaCO_3 > SrCO_3 > BaCO_3$. Statement $I$ is correct.For alkali metal carbonates $(Group \ 1)$,the solubility increases down the group because the hydration energy decreases less rapidly than the lattice energy as the cation size increases. Thus,the order is $Li_2CO_3 Statement $IV$ is incorrect as it contradicts the trend for alkali metal carbonates.Therefore,the correct statements are $I, II, III$.

Column-$I$ (Compound)	Column-$II$ (Products of heating effect)
$a$. $LiNO_3$	$P$. Metal oxide
$b$. $FeSO_4 \cdot 7H_2O$	$Q$. Paramagnetic gas
$c$. $NaHCO_3$	$R$. Acidic gas
$d$. $BeCO_3$	$S$. Evolved gas has same number of $\sigma$ and $\pi$ bonds

The correct solubility order is/are:
$I. CaCO_3 > SrCO_3 > BaCO_3$
$II. Li_2CO_3 < Na_2CO_3 < K_2CO_3$
$III. K_2CO_3 < Rb_2CO_3 < Cs_2CO_3$
$IV. Na_2CO_3 > K_2CO_3 > Rb_2CO_3$

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The correct solubility order is/are:$I. CaCO_3 > SrCO_3 > BaCO_3$$II. Li_2CO_3 < Na_2CO_3 < K_2CO_3$$III. K_2CO_3 < Rb_2CO_3 < Cs_2CO_3$$IV. Na_2CO_3 > K_2CO_3 > Rb_2CO_3$