The correct sequence of reagents for the following conversion will be:

Which of the following pairs of reactants is most effective in forming an enamine?

When an aldehyde is treated with an excess of monohydric alcohol,what is formed?

The product which is not expected to be formed in the following reaction is:
$C_6H_5CHO + CH_3CH_2CHO \xrightarrow{OH^-(aq.), \Delta} \text{Product}$

Which of the following can be distinguished by the iodoform reaction?

Match List-$I$ with List-$II$.
List-$I$ (Reaction):
$A$. Bicyclohexylidene $\rightarrow$ $2$ Cyclohexanone
$B$. Benzene $\rightarrow$ Benzophenone
$C$. Cyclohexanol $\rightarrow$ Cyclohexanone
$D$. Ethylbenzene $\rightarrow$ Potassium benzoate
List-$II$ (Reagents/Condition):
$I$. Benzoyl chloride / Anhydrous $AlCl_3$
$II$. $CrO_3$
$III$. $KMnO_4 / KOH, \Delta$
$IV$. $(i) O_3, (ii) Zn-H_2O$
Choose the correct answer from the options given below: