The correct relationship between the standard free energy change in a reaction and the corresponding equilibrium constant $K_c$ is:

  • A
    $\Delta G = RT \ln K_c$
  • B
    $-\Delta G = RT \ln K_c$
  • C
    $\Delta G^o = RT \ln K_c$
  • D
    $-\Delta G^o = RT \ln K_c$

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Similar Questions

Which of the following relations is incorrect?

For a reaction,$\Delta G^{\circ} = -115 \, kJ$. What is the value of $\log \, K_p$ at $298 \, K$?

For a homogeneous gaseous reaction,the equilibrium constant $K_p$ is $10^{-8}$. The standard Gibbs free energy change for the reaction is ........... $kcal$. $(R = 2.0 \, cal \, K^{-1} \, mol^{-1}, T = 298 \, K)$

In the equilibrium state,the value of $\Delta G$ is:

For the reaction $A_{(g)} \rightarrow B_{(g)},$ the value of the equilibrium constant at $300 \ K$ and $1 \ atm$ is equal to $100.0.$ The value of $\Delta_{r}G^{\circ}$ for the reaction at $300 \ K$ and $1 \ atm$ in $J \ mol^{-1}$ is $-xR,$ where $x$ is ........... (Rounded off to the nearest integer) ($R = 8.31 \ J \ mol^{-1} K^{-1}$ and $\ln 10 = 2.3$)

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