The correct order regarding electronegativity | vedclass

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Question

(B) The electronegativity $(EN)$ of hybrid orbitals is directly proportional to the percentage of $s$-character in the hybrid orbital.For $sp$ hybridi

Vedclass · Accepted Answer

$sp > sp^2 > sp^3$

Vedclass · Answer

(B) The electronegativity $(EN)$ of hybrid orbitals is directly proportional to the percentage of $s$-character in the hybrid orbital.For $sp$ hybridization,the $s$-character is $50\%$.For $sp^2$ hybridization,the $s$-character is $33.3\%$.For $sp^3$ hybridization,the $s$-character is $25\%$.Therefore,the order of electronegativity is $sp (50\%) > sp^2 (33.3\%) > sp^3 (25\%)$.

The correct order regarding electronegativity of hybrid orbitals of carbon is

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