The correct order of the number of unpaired e | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) . $[Fe(CN)_6]^{3-}$: $Fe^{3+}$ is $d^5$. $CN^-$ is a strong field ligand,so pairing occurs. $n = 1$.$B$. $[FeF_6]^{3-}$: $Fe^{3+}$ is $d^5$. $F^-$

Vedclass · Accepted Answer

$E < A < D < C < B$

Vedclass · Answer

(B) . $[Fe(CN)_6]^{3-}$: $Fe^{3+}$ is $d^5$. $CN^-$ is a strong field ligand,so pairing occurs. $n = 1$.$B$. $[FeF_6]^{3-}$: $Fe^{3+}$ is $d^5$. $F^-$ is a weak field ligand,so no pairing. $n = 5$.$C$. $[CoF_6]^{3-}$: $Co^{3+}$ is $d^6$. $F^-$ is a weak field ligand,so no pairing. $n = 4$.$D$. $[Cr(oxalate)_3]^{3-}$: $Cr^{3+}$ is $d^3$. $n = 3$.$E$. $[Ni(CO)_4]$: $Ni^0$ is $d^{10}$. $CO$ is a strong field ligand,all electrons paired. $n = 0$.The number of unpaired electrons are: $A=1, B=5, C=4, D=3, E=0$.Ordering them: $E(0) Thus,the correct order is $E < A < D < C < B$.

The correct order of the number of unpaired electrons in the given complexes is
$A$. $[Fe(CN)_6]^{3-}$; $B$. $[FeF_6]^{3-}$; $C$. $[CoF_6]^{3-}$; $D$. $[Cr(oxalate)_3]^{3-}$; $E$. $[Ni(CO)_4]$
Choose the correct answer from the options given below:

Similar Questions

Which of the following complex compounds will exhibit highest paramagnetic behaviour?
(At. No. $Ti = 22, Cr = 24, Co = 27, Zn = 30$)

What kind of isomerism exists between $[Cr(H_2O)_6]Cl_3$ and $[Cr(H_2O)_5Cl]Cl_2 \cdot H_2O$?

The calculated spin-only magnetic moments $(BM)$ of the species $[Fe(CN)_6]^{4-}$ and $[Fe(H_2O)_6]^{2+}$,respectively,are:

Select the correct order of the property indicated against them:

Which of the following species shows the maximum magnetic moment?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The correct order of the number of unpaired electrons in the given complexes is$A$. $[Fe(CN)_6]^{3-}$; $B$. $[FeF_6]^{3-}$; $C$. $[CoF_6]^{3-}$; $D$. $[Cr(oxalate)_3]^{3-}$; $E$. $[Ni(CO)_4]$Choose the correct answer from the options given below: