The correct order of sulphur-oxygen bond orde | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The bond order is calculated as the total number of bonds divided by the number of resonating structures or the number of terminal atoms.$1$. For

Vedclass · Accepted Answer

$S_2O_3^{2-} < SO_4^{2-} < SO_3$

Vedclass · Answer

(C) The bond order is calculated as the total number of bonds divided by the number of resonating structures or the number of terminal atoms.$1$. For $SO_3$: The structure has $3$ resonance hybrids where $6$ bonds are distributed over $3$ $S-O$ positions. Bond order $= \frac{6}{3} = 2.0$.$2$. For $SO_4^{2-}$: The structure has $4$ equivalent $S-O$ bonds with a total of $6$ bonds in the resonance hybrid. Bond order $= \frac{6}{4} = 1.5$.$3$. For $S_2O_3^{2-}$: The structure involves a central sulphur atom bonded to three oxygen atoms and one sulphur atom. The resonance involves $4$ bonds distributed over $3$ $S-O$ positions. Bond order $= \frac{4}{3} \approx 1.33$.Comparing the values: $1.33 Thus,the correct order is $S_2O_3^{2-} < SO_4^{2-} < SO_3$.

The correct order of sulphur-oxygen bond order in $SO_3$,$S_2O_3^{2-}$,and $SO_4^{2-}$ is:

Similar Questions

What is the $O-O$ bond length in the ozone $(O_3)$ molecule (in $pm$)?

The bond order of individual carbon-carbon bonds in benzene is

In the given $HNO_3$ molecule,identify the bond lengths $a$ and $b$ (where $a$ and $b$ are bond lengths).

Draw the resonating structures of $(A)$ Ozone molecule $(O_3)$ and $(B)$ Nitrate ion $(NO_3^-)$.

What will be the resonance energy of $N_2O$ from the following data: $\Delta H_f(N_2O) = 82 \ kJ \ mol^{-1}$. Bond energies of $N \equiv N$,$N = N$,$O = O$,and $N = O$ bonds are $946$,$418$,$498$,and $607 \ kJ \ mol^{-1}$ respectively.

Vedclass Test Series

Exam Paper Generator

Online Exam Module