The correct order of stability for the given | vedclass

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(B) To determine the stability of canonical structures,we follow these rules:$1$. Structures with more covalent bonds are more stable.$2$. Structures

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$III > I > II$

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(B) To determine the stability of canonical structures,we follow these rules:$1$. Structures with more covalent bonds are more stable.$2$. Structures with complete octets for all atoms are more stable.$3$. Negative charge on a more electronegative atom (like $O$) is more stable than on a less electronegative atom (like $C$).Analyzing the structures:- Structure $(III)$ has the maximum number of covalent bonds and all atoms (except $H$) have complete octets. Thus,it is the most stable.- Structure $(I)$ has a negative charge on the carbon atom.- Structure $(II)$ has a negative charge on the oxygen atom but also has adjacent opposite charges (a dipole),which makes it less stable than $(I)$ due to charge separation.- Therefore,the stability order is $(III) > (I) > (II)$.

The correct order of stability for the given canonical structures is:
$(I)$ $H-C(=O)-CH_2^-$
$(II)$ $H-C(O^-)(^+)-CH_2^-$
$(III)$ $H-C(O^-)=CH_2$

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The correct order of stability for the given canonical structures is:$(I)$ $H-C(=O)-CH_2^-$ $(II)$ $H-C(O^-)(^+)-CH_2^-$ $(III)$ $H-C(O^-)=CH_2$