The correct order of priority of groups -SCH_ | vedclass

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(B) According to the $CIP$ (Cahn-Ingold-Prelog) priority rules,priority is assigned based on the atomic number of the atom directly attached to the ch

Vedclass · Accepted Answer

$IV, III, II, I$

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(B) According to the $CIP$ (Cahn-Ingold-Prelog) priority rules,priority is assigned based on the atomic number of the atom directly attached to the chiral center.$1$. The atoms attached are: $S$ (atomic number $16$) for $-SCH_3$,$N$ (atomic number $7$) for $-NO_2$,$C$ (atomic number $6$) for $-C \equiv CH$,and $C$ (atomic number $6$) for $-CH_2C_6H_5$.$2$. Comparing these,$S$ has the highest atomic number,so $-SCH_3$ $(I)$ has the highest priority.$3$. Next is $N$ in $-NO_2$ $(II)$.$4$. Comparing the two carbon-based groups: $-C \equiv CH$ $(III)$ is treated as being bonded to three carbons (due to triple bond),whereas $-CH_2C_6H_5$ $(IV)$ is bonded to one carbon and two hydrogens. Thus,$-C \equiv CH$ has higher priority than $-CH_2C_6H_5$.$5$. The decreasing order of priority is $I > II > III > IV$.$6$. Therefore,the increasing order of priority is $IV < III < II < I$.

The correct order of priority of groups $-SCH_3$ $(I)$,$-NO_2$ $(II)$,$-C \equiv CH$ $(III)$,and $-CH_2C_6H_5$ $(IV)$,on the basis of $CIP$ classification,is (increasing order):

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