The correct order of ionic radii of Ce,La,Pm | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In the lanthanoid series,as we move from $La$ $(Z=57)$ to $Lu$ $(Z=71)$,the ionic radii of the $+3$ ions decrease regularly. This phenomenon is kn

Vedclass · Accepted Answer

$Yb^{+3} < Pm^{+3} < Ce^{+3} < La^{+3}$

Vedclass · Answer

(D) In the lanthanoid series,as we move from $La$ $(Z=57)$ to $Lu$ $(Z=71)$,the ionic radii of the $+3$ ions decrease regularly. This phenomenon is known as lanthanoid contraction.This decrease occurs because the $4f$ electrons are added,which provide poor shielding for the increasing nuclear charge,leading to a stronger attraction between the nucleus and the outer electrons.The atomic numbers are: $La$ $(57)$,$Ce$ $(58)$,$Pm$ $(61)$,and $Yb$ $(70)$.Therefore,the order of ionic radii is $La^{+3} > Ce^{+3} > Pm^{+3} > Yb^{+3}$,which is equivalent to $Yb^{+3} < Pm^{+3} < Ce^{+3} < La^{+3}$.

The correct order of ionic radii of $Ce$,$La$,$Pm$ and $Yb$ in $+3$ oxidation state is

Similar Questions

Which of the following lanthanoids exhibits no effective magnetic moment in the $+3$ oxidation state?

Limiting compositions of $f$-block hydrides are

Which of the following $f$-block elements exhibits the highest oxidation state?

Which one of the following lanthanide ions does not exhibit paramagnetism?

The incorrect statement among the following is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module