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(C) The intensity of color in coordination complexes is related to the probability of $d-d$ transitions. Complexes that lack a center of inversion (li

Vedclass · Accepted Answer

$[NiCl_{4}]^{2-} > [Ni(H_{2}O)_{6}]^{2+} > [Ni(CN)_{4}]^{2-}$

Vedclass · Answer

(C) The intensity of color in coordination complexes is related to the probability of $d-d$ transitions. Complexes that lack a center of inversion (like tetrahedral complexes) exhibit more intense colors due to the relaxation of the Laporte selection rule compared to centrosymmetric complexes (like octahedral or square planar complexes).The complexes are: $[NiCl_{4}]^{2-}$ (tetrahedral,non-centrosymmetric),$[Ni(H_{2}O)_{6}]^{2+}$ (octahedral,centrosymmetric),and $[Ni(CN)_{4}]^{2-}$ (square planar,centrosymmetric).Thus,the intensity order is: $[NiCl_{4}]^{2-} > [Ni(H_{2}O)_{6}]^{2+} > [Ni(CN)_{4}]^{2-}$.

The correct order of intensity of colors of the compounds is:

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