The correct order of equivalent conductances | vedclass

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(B) The equivalent conductance $(\Lambda_{eq})$ at infinite dilution depends on the ionic mobility of the ions in the solvent. In water,$H^{+}$ and $H

Vedclass · Accepted Answer

$H^{+} > HO^{-} > K^{+} > CH_{3}COO^{-}$

Vedclass · Answer

(B) The equivalent conductance $(\Lambda_{eq})$ at infinite dilution depends on the ionic mobility of the ions in the solvent. In water,$H^{+}$ and $HO^{-}$ ions exhibit exceptionally high ionic mobilities due to the Grotthuss mechanism (proton hopping). Among the given ions,$H^{+}$ has the highest mobility,followed by $HO^{-}$. $K^{+}$ is a simple hydrated cation with moderate mobility,while $CH_{3}COO^{-}$ is a large polyatomic anion with relatively lower mobility. Therefore,the correct order of equivalent conductances at infinite dilution is $H^{+} > HO^{-} > K^{+} > CH_{3}COO^{-}$.

The correct order of equivalent conductances at infinite dilution in water at room temperature for $H^{+}$,$K^{+}$,$CH_{3}COO^{-}$ and $HO^{-}$ ions is

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