The correct order of dipole moment is:

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(D) The dipole moment $(\mu)$ depends on the polarity of bonds and the geometry of the molecule.
$CH_4$ is a symmetric tetrahedral molecule with a ne

Vedclass · Accepted Answer

$H_2O > NH_3 > CH_4$

Vedclass · Answer

(D) The dipole moment $(\mu)$ depends on the polarity of bonds and the geometry of the molecule.
$CH_4$ is a symmetric tetrahedral molecule with a net dipole moment of $0 \ D$.
$NH_3$ has a trigonal pyramidal geometry with a lone pair,resulting in a dipole moment of approximately $1.47 \ D$.
$H_2O$ has a bent geometry with two lone pairs,resulting in a higher dipole moment of approximately $1.85 \ D$.
Therefore,the correct order of dipole moment is $H_2O > NH_3 > CH_4$.

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