The correct order of decreasing second ionisa | vedclass

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Question

The amount of energy required to remove an electron from unipositive ion is referred as second İonisation potential.

In $Ti, V, Cr$ and $Mn$, gener

Vedclass · Accepted Answer

$Cr > Mn > V > Ti$

Vedclass · Answer

The amount of energy required to remove an electron from unipositive ion is referred as second İonisation potential.

In $Ti, V, Cr$ and $Mn$, generally second ionisation energy increases with increase in atomic number but second ionisation potential of $Cr$ is greater than

that of $Mn$ due to the presence of exactly half-filled $d-$subshell in $Cr$. Thus, the order of second ionisation enthalpy is

$\mathrm{Cr}>\mathrm{Mn}>\mathrm{V}>\mathrm{Ti}$

The correct order of decreasing second ionisation enthalpy of $Ti(22), V(23), Cr(24)$ and $Mn(25)$ is

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