The correct order of bond angles of the molec | vedclass

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Question

(D) The bond angles for the given molecules are as follows:$1.$ $HgCl_2$: Linear geometry ($sp$ hybridization),bond angle = $180^{\circ}$.$2.$ $SO_3$:

Vedclass · Accepted Answer

$HgCl_2 > SO_3 > SiCl_4 > NH_3$

Vedclass · Answer

(D) The bond angles for the given molecules are as follows:$1.$ $HgCl_2$: Linear geometry ($sp$ hybridization),bond angle = $180^{\circ}$.$2.$ $SO_3$: Trigonal planar geometry ($sp^2$ hybridization),bond angle = $120^{\circ}$.$3.$ $SiCl_4$: Tetrahedral geometry ($sp^3$ hybridization),bond angle = $109.5^{\circ}$.$4.$ $NH_3$: Trigonal pyramidal geometry ($sp^3$ hybridization with one lone pair),bond angle = $107^{\circ}$.Therefore,the correct order is $HgCl_2 > SO_3 > SiCl_4 > NH_3$.

List-$I$ (molecules/ions)	List-$II$ (No. of lone pairs of $e^-$ on central atom)
$A$. $IF_7$	$I$. Three
$B$. $ICl_4^-$	$II$. One
$C$. $XeF_6$	$III$. Two
$D$. $XeF_2$	$IV$. Zero

The correct order of bond angles of the molecules $SiCl_4$,$SO_3$,$NH_3$,and $HgCl_2$ is:

Similar Questions

Match List-$I$ with List-$II$.

List-$I$ (molecules/ions) List-$II$ (No. of lone pairs of $e^-$ on central atom)

$A$. $IF_7$ $I$. Three

$B$. $ICl_4^-$ $II$. One

$C$. $XeF_6$ $III$. Two

$D$. $XeF_2$ $IV$. Zero

Choose the correct answer from the options given below:

The number of bond pairs of electrons and the total number of lone pairs of electrons in $XeOF_4$ are respectively:

What is the bond angle $O-S-O$ in the $SO_2$ molecule (in $^{\circ}$)?

Assertion : All $F-S-F$ angles in $SF_4$ are greater than $90^\circ$ but less than $180^\circ$.
Reason : The lone pair-bond pair repulsion is weaker than bond pair-bond pair repulsion.

In the following three-dimensional structure of $CH_4$,the bonds are labelled as $W, X, Y$ and $Z$. The bonds projecting out of the plane are:

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