The correct order of boiling points of the be | vedclass

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(D) Methoxybenzene (Structure $I$) is an ether and cannot form intermolecular hydrogen bonds,so it has the lowest boiling point.Both $m$-cresol (Struc

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$II > III > I$

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(D) Methoxybenzene (Structure $I$) is an ether and cannot form intermolecular hydrogen bonds,so it has the lowest boiling point.Both $m$-cresol (Structure $II$) and $o$-cresol (Structure $III$) are phenols and can form intermolecular hydrogen bonds,leading to higher boiling points than $I$.Between $m$-cresol and $o$-cresol,$o$-cresol exhibits intramolecular hydrogen bonding,which reduces the extent of intermolecular hydrogen bonding compared to $m$-cresol.Therefore,$m$-cresol has a higher boiling point than $o$-cresol.The correct order of boiling points is $II > III > I$.

The correct order of boiling points of the below compounds is:
$(I)$ Methoxybenzene
$(II)$ $m$-Cresol
$(III)$ $o$-Cresol

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The correct order of boiling points of the below compounds is:$(I)$ Methoxybenzene$(II)$ $m$-Cresol$(III)$ $o$-Cresol