The correct order of E^{circ}_{M^{2+}/M} valu | vedclass

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Question

(A) The standard electrode potentials $(E^{\circ}_{M^{2+}/M})$ for the given elements are:$E^{\circ}_{Mn^{2+}/Mn} = -1.18 \ V$$E^{\circ}_{Cr^{2+}/Cr}

Vedclass · Accepted Answer

$Mn > Cr > Fe > Co$

Vedclass · Answer

(A) The standard electrode potentials $(E^{\circ}_{M^{2+}/M})$ for the given elements are:$E^{\circ}_{Mn^{2+}/Mn} = -1.18 \ V$$E^{\circ}_{Cr^{2+}/Cr} = -0.91 \ V$$E^{\circ}_{Fe^{2+}/Fe} = -0.44 \ V$$E^{\circ}_{Co^{2+}/Co} = -0.28 \ V$Comparing the magnitudes of these negative values,the order of $E^{\circ}_{M^{2+}/M}$ values is $Mn  Cr > Fe > Co$,option $A$ is the intended answer.

The correct order of $E^{\circ}_{M^{2+}/M}$ values for the four successive elements $Cr$,$Mn$,$Fe$,and $Co$ is:

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