The correct order of E^o M^{2+}/M values with | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The standard electrode potential ($E^o$ $M^{2+}/M$) values for the first transition series generally become less negative as we move from left to

Vedclass · Accepted Answer

$Mn > Cr > Fe > Co$

Vedclass · Answer

(B) The standard electrode potential ($E^o$ $M^{2+}/M$) values for the first transition series generally become less negative as we move from left to right,with some exceptions.$Mn^{2+}$ has a stable $d^5$ configuration,which makes its reduction potential more negative than expected.The electronic configurations of the $M^{2+}$ ions are:$Cr^{2+}$: $[Ar] 3d^4$$Mn^{2+}$: $[Ar] 3d^5$ (half-filled,extra stable)$Fe^{2+}$: $[Ar] 3d^6$$Co^{2+}$: $[Ar] 3d^7$Due to the extra stability of the $Mn^{2+}$ ion,the $E^o$ value for $Mn^{2+}/Mn$ is more negative than that of $Cr^{2+}/Cr$. The overall order of the magnitude of negative values is $Mn > Cr > Fe > Co$.

The correct order of $E^o$ $M^{2+}/M$ values with negative sign for the four successive elements $Cr$,$Mn$,$Fe$ and $Co$ is

Similar Questions

Which element is named after the name of a planet?

The period number and group number of Tantalum $(Z = 73)$ are respectively:

Which of the following elements exhibits ferromagnetic properties?

Statement-$I$: Mercury is liquid at room temperature.
Statement-$II$: In mercury,there is no unpaired $d$-electron and thus,metallic bonding is weakest.

Which of the following electronic configurations represents a transition element?

Vedclass Test Series

Exam Paper Generator

Online Exam Module