The correct order for E_2 reaction with alc. | vedclass

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(A) The rate of $E_2$ reaction depends on the stability of the transition state and the ease of forming the double bond. In compound $(i)$,the presenc

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$(i) > (ii) > (iii)$

Vedclass · Answer

(A) The rate of $E_2$ reaction depends on the stability of the transition state and the ease of forming the double bond. In compound $(i)$,the presence of a double bond in the ring makes the formation of a conjugated system or a more stable alkene easier upon elimination. In compound $(ii)$,the chlorine is attached to a carbon adjacent to a double bond (allylic position),which facilitates the elimination reaction due to the formation of a conjugated diene system. In compound $(iii)$,it is a simple secondary alkyl halide without any activating double bonds,making it the least reactive towards $E_2$ elimination compared to the others. Thus,the reactivity order is $(i) > (ii) > (iii)$.

The correct order for $E_2$ reaction with alc. $KOH$ will be

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