The correct IUPAC nomenclature for the follow | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $1$. Identify the principal functional group: The carboxylic acid group $(-COOH)$ has higher priority than the ketone group $(C=O)$. Thus,the pare

Vedclass · Accepted Answer

$2-$Methyl$-5-$oxohexanoic acid

Vedclass · Answer

(B) $1$. Identify the principal functional group: The carboxylic acid group $(-COOH)$ has higher priority than the ketone group $(C=O)$. Thus,the parent chain is named as an alkanoic acid.$2$. Number the chain: Start numbering from the carbon of the $-COOH$ group as $C-1$. The chain is numbered as follows: $C-1$ $(-COOH)$,$C-2$ $(-CH(CH_3)-)$,$C-3$ $(-CH_2-)$,$C-4$ $(-CH_2-)$,$C-5$ $(C=O)$,$C-6$ $(-CH_3)$.$3$. Identify substituents and functional groups: There is a methyl group at position $2$ and a ketone group at position $5$. The ketone group is named as an 'oxo' substituent.$4$. Assemble the name: $2-$Methyl$-5-$oxohexanoic acid.

The correct $IUPAC$ nomenclature for the following compound is

Similar Questions

What is the $IUPAC$ name of the compound $CH_3-CO-CH_2-CH(OH)-CHO$?

The $IUPAC$ name of the given compound is:

The structure of the compound whose $IUPAC$ name is $3-$ethyl$-2-$hydroxy$-4-$methylhex$-3-$en$-5-$ynoic acid is:

The $IUPAC$ name for the structure $CH_3-CH(OC_2H_5)-CH_2-CH_2-CH_3$ is:

The structure of the compound whose $IUPAC$ name is $3-$ethyl$-2-$hydroxy$-4-$methylhex$-3-$en$-5-$ynoic acid is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module