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(A) The van der Waals constant $a$ represents the magnitude of attractive forces between gas molecules. Larger molecules or those with higher polariza

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$H_2 < O_2 < CH_4$

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(A) The van der Waals constant $a$ represents the magnitude of attractive forces between gas molecules. Larger molecules or those with higher polarizability generally have higher values of $a$.From the provided table:For $H_2$,$a = 0.244 \ 	ext{atm L}^2 	ext{mol}^{-2}$For $O_2$,$a = 1.36 \ 	ext{atm L}^2 	ext{mol}^{-2}$For $CH_4$,$a = 2.25 \ 	ext{atm L}^2 	ext{mol}^{-2}$Comparing these values,the increasing order is $0.244 < 1.36 < 2.25$,which corresponds to $H_2 < O_2 < CH_4$.

The correct increasing order of the value of van der Waals's constant $a$ for $CH_4, O_2$ and $H_2$ gases is

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