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(C) For a satellite of mass $m$ orbiting a planet of mass $M$ at a distance $r$ from its center,the energies are given by:Potential Energy: $U = -\fra

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(C) For a satellite of mass $m$ orbiting a planet of mass $M$ at a distance $r$ from its center,the energies are given by:Potential Energy: $U = -\frac{GMm}{r}$Kinetic Energy: $K = \frac{GMm}{2r}$Total Energy: $E = U + K = -\frac{GMm}{2r}$From these expressions:$1$. $U$ is always negative and its magnitude decreases as $r$ increases,approaching $0$ from below.$2$. $K$ is always positive and decreases as $r$ increases,approaching $0$ from above.$3$. $E$ is always negative and its magnitude decreases as $r$ increases,approaching $0$ from below.$4$. Comparing magnitudes: $|U| = 2|E|$ and $K = |E|$.Thus,$U$ and $E$ are negative curves,while $K$ is a positive curve. As $r 	o \infty$,all energies approach $0$. The correct graph shows $K$ above the $r$-axis,and both $U$ and $E$ below the $r$-axis,with $U$ being more negative than $E$ (i.e.,$|U| > |E|$). This corresponds to the graph where $K$ is positive,$E$ is the top negative curve,and $U$ is the bottom negative curve.

The correct graph representing the variation of total energy $(E_t)$,kinetic energy $(E_k)$,and potential energy $(U)$ of a satellite with its distance $(r)$ from the centre of the Earth is:

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