The correct electron dot structure of a water | vedclass

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Question

(A) water molecule $(H_2O)$ consists of one oxygen atom bonded to two hydrogen atoms.Oxygen has $6$ valence electrons and requires $2$ more to complet

Vedclass · Accepted Answer

$H:\underset{\centerdot \,\centerdot }{\overset{\centerdot \,\centerdot }{\mathop{O}}}\,:H$

Vedclass · Answer

(A) water molecule $(H_2O)$ consists of one oxygen atom bonded to two hydrogen atoms.Oxygen has $6$ valence electrons and requires $2$ more to complete its octet.Each hydrogen atom has $1$ valence electron and requires $1$ more to complete its duplet.Oxygen shares one electron with each hydrogen atom,forming two covalent bonds.This leaves two lone pairs of electrons on the oxygen atom.The correct electron dot structure represents the shared pairs as colons $(:)$ and shows the lone pairs on the oxygen atom as two pairs of dots.Thus,the structure is $H:\underset{\centerdot \,\centerdot }{\overset{\centerdot \,\centerdot }{\mathop{O}}}\,:H$.

The correct electron dot structure of a water molecule is:

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