The correct decreasing order of the following | vedclass

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(B) The oxidizing and fluorinating power of xenon fluorides depends on the ability of the $Xe$ atom to get reduced,which is directly related to the ox

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$XeF_6 > XeF_4 > XeF_2$

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(B) The oxidizing and fluorinating power of xenon fluorides depends on the ability of the $Xe$ atom to get reduced,which is directly related to the oxidation state of $Xe$ in the compound.In $XeF_6$,the oxidation state of $Xe$ is $+6$.In $XeF_4$,the oxidation state of $Xe$ is $+4$.In $XeF_2$,the oxidation state of $Xe$ is $+2$.As the oxidation state increases,the tendency to get reduced increases,making the compound a stronger oxidizing and fluorinating agent.Therefore,the correct decreasing order is $XeF_6 > XeF_4 > XeF_2$.

The correct decreasing order of the following $Xe$ compounds to act as both fluorinating and oxidizing agent is
$(I)$ $XeF_6$
$(II)$ $XeF_4$
$(III)$ $XeF_2$

Similar Questions

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Which of the following chemical reactions of xenon is $NOT$ correct?

Which of the following statements is $NOT$ true for noble gases?

Assertion $(A)$: All noble gases are monoatomic.
Reason $(R)$: All noble gases have very low melting and boiling points.

In $XeF_2, XeF_4, XeF_6$,the number of lone pairs on $Xe$ is respectively:

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The correct decreasing order of the following $Xe$ compounds to act as both fluorinating and oxidizing agent is$(I)$ $XeF_6$$(II)$ $XeF_4$$(III)$ $XeF_2$