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(B) $1$. The first structure has the $-OH$ group on the right at the chiral carbon (penultimate carbon),identifying it as a $D$-sugar. Since both $-OH

Vedclass · Accepted Answer

$D$-erythrose,$D$-threose,$L$-erythrose,$L$-threose

Vedclass · Answer

(B) $1$. The first structure has the $-OH$ group on the right at the chiral carbon (penultimate carbon),identifying it as a $D$-sugar. Since both $-OH$ groups are on the same side,it is $D$-erythrose.$2$. The second structure has the $-OH$ group on the right at the chiral carbon,identifying it as a $D$-sugar. Since the $-OH$ groups are on opposite sides,it is $D$-threose.$3$. The third structure has the $-OH$ group on the left at the chiral carbon,identifying it as an $L$-sugar. Since both $-OH$ groups are on the same side,it is $L$-erythrose.$4$. The fourth structure has the $-OH$ group on the left at the chiral carbon,identifying it as an $L$-sugar. Since the $-OH$ groups are on opposite sides,it is $L$-threose.Therefore,the correct order is $D$-erythrose,$D$-threose,$L$-erythrose,$L$-threose.

The correct corresponding names of the four aldoses with the configurations given below,respectively,are:

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