The correct IUPAC name of the given compound | vedclass

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Question

(D) To determine the $IUPAC$ name,we identify the principal functional group,which is the ketone group $(-one)$.We number the ring starting from the k

Vedclass · Accepted Answer

$5-$hydroxy cyclohex$-3-$en$-1-$one

Vedclass · Answer

(D) To determine the $IUPAC$ name,we identify the principal functional group,which is the ketone group $(-one)$.We number the ring starting from the ketone carbon as $C-1$.We then number the ring to give the lowest possible locants to the double bond and the hydroxyl group.Starting from the ketone carbon $(C-1)$,we proceed towards the double bond to give it the lowest locant ($C-3$ to $C-4$ double bond).Thus,the hydroxyl group is at position $5$.The correct $IUPAC$ name is $5-$hydroxycyclohex$-3-$en$-1-$one.

The correct $IUPAC$ name of the given compound is

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