The correct IUPAC name of the given compound | vedclass

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(B) $1$. Identify the principal functional group: The carboxylic acid group $(-COOH)$ has higher priority than the ester group $(-O-CO-CH_3)$. Thus,th

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$4-$Ethanoyloxycyclopent$-2-$ene carboxylic acid

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(B) $1$. Identify the principal functional group: The carboxylic acid group $(-COOH)$ has higher priority than the ester group $(-O-CO-CH_3)$. Thus,the parent chain is a cyclopentene carboxylic acid. $2$. Numbering the ring: Start numbering from the carbon attached to the $-COOH$ group as $C-1$. To give the double bond the lowest possible locant,proceed towards the double bond. Thus,the double bond starts at $C-2$. $3$. Identify substituents: The $-O-CO-CH_3$ group is an ethanoyloxy group (or acetoxy group) located at the $C-4$ position. $4$. Combine the parts: The name is $4-$ethanoyloxycyclopent$-2-$ene$-1-$carboxylic acid,which is commonly written as $4-$ethanoyloxycyclopent$-2-$ene carboxylic acid.

The correct $IUPAC$ name of the given compound is:

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