The coordination number and oxidation number | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The coordination number is determined by the total number of donor atoms directly bonded to the central metal atom $X$. Here,$SO_4^{2-}$ acts as a

Vedclass · Accepted Answer

$6$ and $3$

Vedclass · Answer

(D) The coordination number is determined by the total number of donor atoms directly bonded to the central metal atom $X$. Here,$SO_4^{2-}$ acts as a bidentate ligand (or monodentate depending on context,but usually considered as occupying one coordination site in this specific complex geometry) and $5$ $NH_3$ molecules are monodentate. However,in $[X(SO_4)(NH_3)_5]Cl$,$SO_4$ is a bidentate ligand ($2$ sites) and $5$ $NH_3$ are monodentate ($5$ sites),but typically in this specific coordination sphere,$SO_4$ acts as a monodentate ligand. Thus,$1 + 5 = 6$.To find the oxidation state of $X$:Let the oxidation state of $X$ be $x$.The charge of $SO_4$ is $-2$,$NH_3$ is $0$,and the outer $Cl$ is $-1$.The complex is neutral,so: $x + (-2) + 5(0) + (-1) = 0$.$x - 3 = 0$,which gives $x = +3$.Therefore,the coordination number is $6$ and the oxidation number is $3$.

The coordination number and oxidation number of $X$ in the compound $[X(SO_4)(NH_3)_5]Cl$ are respectively:

Similar Questions

The oxidation state of nickel in the complex $K_4[Ni(CN)_4]$ is .......

Which of the following name-formula combinations is not correct?

The formula $[CO(NH_3)_5Cl]^{2+}$ represents which of the following coordination compounds?

The oxidation number of the central metal in $[Pt(NH_3)_2Cl(NO_2)]$ and $[CoCl_2(en)_2]^{\oplus}$,respectively,are

The oxidation state of cobalt in the complex compound $[Co(NH_3)_6]Cl_3$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module