The converse of [p wedge (sim q)] rightarrow | vedclass

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Question

(D) The converse of a conditional statement $A \rightarrow B$ is defined as $B \rightarrow A$. Given the statement $[p \wedge (\sim q)] \rightarrow r$

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$r \rightarrow (p \wedge \sim q)$

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(D) The converse of a conditional statement $A \rightarrow B$ is defined as $B \rightarrow A$. Given the statement $[p \wedge (\sim q)] \rightarrow r$,the converse is $r \rightarrow [p \wedge (\sim q)]$. However,looking at the provided options,there seems to be a misunderstanding in the original problem's solution logic. If we consider the contrapositive of the converse,or if the question intended to ask for the inverse,the options provided do not match the standard definition of a converse. Given the structure of option $D$,$r \rightarrow (p \wedge \sim q)$ is the correct converse.

The converse of $[p \wedge (\sim q)] \rightarrow r$ is

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