The contribution in the total current flowing | vedclass

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(A) The total current $I$ in a semiconductor is the sum of electron current $I_e$ and hole current $I_h$. Given $I_e = (3/4)I$ and $I_h = (1/4)I$.Ther

Vedclass · Accepted Answer

$6 : 5$

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(A) The total current $I$ in a semiconductor is the sum of electron current $I_e$ and hole current $I_h$. Given $I_e = (3/4)I$ and $I_h = (1/4)I$.Therefore,the ratio of currents is $I_e / I_h = (3/4) / (1/4) = 3$.We know that current $I = nqvA$,where $n$ is the concentration,$q$ is the charge,$v$ is the drift velocity,and $A$ is the cross-sectional area.Thus,$I_e / I_h = (n_e q v_e A) / (n_h q v_h A) = (n_e / n_h) 	imes (v_e / v_h)$.Given $v_e = (5/2)v_h$,so $v_e / v_h = 5/2$.Substituting the values: $3 = (n_e / n_h) 	imes (5/2)$.Solving for the ratio of concentrations: $n_e / n_h = 3 	imes (2/5) = 6/5$.Thus,the ratio is $6 : 5$.

The contribution in the total current flowing through a semiconductor due to electrons and holes are $3/4$ and $1/4$ respectively. If the drift velocity of electrons is $5/2$ times that of holes at this temperature,then the ratio of concentration of electrons and holes is

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