The configurations of the complexes of mangan | vedclass

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(D) For complex $A$,the configuration is $t_{2g}^3 e_g^1$,which corresponds to $4$ electrons in the $d$-orbitals. This indicates $Mn^{3+}$ ($d^4$ syst

Vedclass · Accepted Answer

$[Mn(H_2O)_6]^{3+}, [Mn(CN)_6]^{3-}$

Vedclass · Answer

(D) For complex $A$,the configuration is $t_{2g}^3 e_g^1$,which corresponds to $4$ electrons in the $d$-orbitals. This indicates $Mn^{3+}$ ($d^4$ system). Since $H_2O$ is a weak-field ligand,it results in a high-spin complex. Thus,$A$ is $[Mn(H_2O)_6]^{3+}$.For complex $B$,the configuration is $t_{2g}^4 e_g^0$,which also corresponds to $4$ electrons in the $d$-orbitals $(Mn^{3+})$. Since $CN^-$ is a strong-field ligand,it causes pairing of electrons,resulting in a low-spin complex. Thus,$B$ is $[Mn(CN)_6]^{3-}$.

The configurations of the complexes of manganese $A$ and $B$ respectively are $t_{2g}^3 e_g^1$ and $t_{2g}^4 e_g^0$. Then $A$ and $B$ are:

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