The conductivity of $0.012 \ M$ $NaBr$ solution is $2.67 \times 10^{-4} \ S \ cm^{-1}$. What is its molar conductivity?

  • A
    $26.7 \ S \ cm^2 \ mol^{-1}$
  • B
    $32.04 \ S \ cm^2 \ mol^{-1}$
  • C
    $12.2 \ S \ cm^2 \ mol^{-1}$
  • D
    $22.2 \ S \ cm^2 \ mol^{-1}$

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