The condition dQ = dW holds good in which of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to the first law of thermodynamics,the relation is given by:$dQ = dW + dU$ ...$(i)$where $dQ$ is the heat supplied,$dW$ is the work done

Vedclass · Accepted Answer

Isothermal process

Vedclass · Answer

(B) According to the first law of thermodynamics,the relation is given by:$dQ = dW + dU$ ...$(i)$where $dQ$ is the heat supplied,$dW$ is the work done,and $dU$ is the change in internal energy.For an isothermal process,the temperature of the system remains constant.Since internal energy $U$ is a function of temperature only,for an isothermal process,the change in internal energy $dU = 0$.Substituting $dU = 0$ into equation $(i)$,we get:$dQ = dW + 0$$dQ = dW$Therefore,the condition $dQ = dW$ holds good for an isothermal process.

The condition $dQ = dW$ holds good in which of the following?

Similar Questions

$A$ thermodynamic process in which the temperature $T$ of the system remains constant,although other variables $P$ and $V$ may change,is called:

In an isothermal process,the volume of an ideal gas is halved. One can say that:

If an ideal gas is compressed isothermally,then:

During which of the following thermodynamic processes represented by a $PV$ diagram can the heat energy absorbed by the system be equal to the area under the $PV$ graph?

When an ideal gas in a cylinder was compressed isothermally by a piston,the work done on the gas was found to be $1.5 \times 10^4 \ J$. During this process,about:

Vedclass Test Series

Exam Paper Generator

Online Exam Module