The concentration of a saturated solution of $Mg(OH)_2$ is $8.2 \times 10^{-4} \ g \ L^{-1}$ at $298 \ K$. Calculate its solubility product $(K_{sp})$. (Molar mass of $Mg(OH)_2 = 58 \ g \ mol^{-1}$)

  • A
    $1.121 \times 10^{-14}$
  • B
    $2.242 \times 10^{-14}$
  • C
    $4.484 \times 10^{-14}$
  • D
    $8.968 \times 10^{-14}$

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