The concentration of H_{3}O^{+} in 1,M,H_{2}S | vedclass

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Question

(C) $H_{2}SO_{4}$ is a strong diprotic acid that dissociates completely in an aqueous solution according to the following equation:$H_{2}SO_{4} \right

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(C) $H_{2}SO_{4}$ is a strong diprotic acid that dissociates completely in an aqueous solution according to the following equation:$H_{2}SO_{4} ightarrow 2H^{+} + SO_{4}^{2-}$Since $H^{+}$ ions react with water to form hydronium ions $(H_{3}O^{+})$,the reaction can be represented as:$H_{2}SO_{4} + 2H_{2}O ightarrow 2H_{3}O^{+} + SO_{4}^{2-}$From the stoichiometry of the reaction,$1$ mole of $H_{2}SO_{4}$ produces $2$ moles of $H_{3}O^{+}$.Therefore,for a $1\,M$ solution of $H_{2}SO_{4}$,the concentration of $H_{3}O^{+}$ will be $2 	imes 1\,M = 2\,M$.

The concentration of $H_{3}O^{+}$ in $1\,M\,H_{2}SO_{4}$ aqueous solution is $.......$ (in $,M$)

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